Answer:
D. 230 N
Explanation:
The magnitude of the electric force between the two protons is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
[tex]q_1 = q_2 = 1.6\cdot 10^{-19} C[/tex] is the charge of each proton
[tex]r=1\cdot 10^{-15} m[/tex] is the distance between the two protons
Substituting numbers into the formula, we find
[tex]F=(9\cdot 10^9 N m^2 C^{-2}) \frac{(1.6\cdot 10^{-19} C)^2}{(1\cdot 10^{-15} m^2)^2}=230.4 N \sim 230 N[/tex]
