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Chris Nazarro had total travel expenses of $872. His transportation cost was $136. The hotel cost was $210 and business materials cost $500. If his lunch cost 30% of his dinner, how much was dinner to the nearest cent?

Respuesta :

calculista

Answer:

[tex]\$20[/tex]

Step-by-step explanation:

Let

x-----> the cost of his lunch

y----> the cost of his dinner

we know that

[tex]x+y=872-136-210-500[/tex]

[tex]x+y=26[/tex] -----> equation A

[tex]x=0.3y[/tex] ---> equation B

substitute equation B in equation A

[tex]0.3y+y=26[/tex]

[tex]1.3y=26[/tex]

[tex]y=\$20[/tex] -----> the cost of the dinner

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