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Television sizes are determined by the length of their diagonal measure. Michael just bought a new television. The height of the television is 40 inches and the length is 71.5 inches. Using the Pythagorean Theorem, what is the size of Michael’s new television? Round your answer to the nearest whole inch (whole number).

Part A: What parts of the right triangle have you been given? Are you looking for a leg or the hypotenuse? The legs have already been given. I’m looking for the hypotenuse.

Part B: Set-up your equation by substituting the correct numbers in to the formula.
71.5^2+40^2=c^2

Part C: Solve for the missing length. Remember to show ALL work for each step.


Part D: What is the size of the television rounded to the nearest whole inch (whole number)?
PART A AND B ARE DONE ALREADY
I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER.

Television sizes are determined by the length of their diagonal measure Michael just bought a new television The height of the television is 40 inches and the l class=

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Answer:

Part A) The legs have already been given. I’m looking for the hypotenuse

Part B) [tex]c^{2}=40^{2} +71.5^{2}[/tex]

Part C) The missing length is [tex]81.93\ in[/tex]

Part D) [tex]82\ in[/tex]

Step-by-step explanation:

Part A) What parts of the right triangle have you been given? Are you looking for a leg or the hypotenuse?

we know that

Applying the Pythagoras Theorem

[tex]c^{2}=a^{2} +b^{2}[/tex]

where

c ----> is the hypotenuse of the right triangle

a and b -------> are the legs of the right triangle

In this problem we have

[tex]a=40\ in[/tex]

[tex]b=71.5\ in[/tex]

so

The legs have already been given. I’m looking for the hypotenuse

Part B) Set-up your equation by substituting the correct numbers in to the formula

we have

[tex]a=40\ in[/tex]

[tex]b=71.5\ in[/tex]

substitute in the Pythagoras Theorem and solve for c (hypotenuse)

[tex]c^{2}=40^{2} +71.5^{2}[/tex]

Part C) Solve for the missing length

we have

[tex]c^{2}=40^{2} +71.5^{2}[/tex]

solve for c

[tex]c^{2}=1,600 +5,112.25[/tex]

[tex]c^{2}=6,712.25[/tex]

[tex]c=\sqrt{6,712.25}\ in[/tex]

[tex]c=81.93\ in[/tex]

Part D) What is the size of the television rounded to the nearest whole inch (whole number)?

[tex]81.93=82\ in[/tex]

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