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carlosego

Answer: 90 pounds.

Step-by-step explanation:

Let's call:

A: pounds of type A coffee.

B: pounds of type B coffee.

Based on the information given in the problem you can set up the following system of equations:

[tex]\left \{ {{A+B=153} \atop {4.25A+5.45B=758.25}} \right.[/tex]

You can use the Elimination method:

- Multiply the first equation by -4.25.

- Add both equations.

- Solve for B.

Then, you obtain:

[tex]\left \{ {{-4.25A-4.25B=-650.25} \atop {4.25A+5.45B=758.25}} \right.\\----------\\1.2B=108\\B=90[/tex]

He used 90 pounds of type B coffee.

alinakincsem

Answer:

B = 90 pounds

Step-by-step explanation:

We know that Han's Coffee shop uses coffee A at $4225 per pound and coffee B at $5.45 per pound and this month it made 153 pounds of blend for a total cost of $758.25.

We are find the number of pounds for coffee B used.

[tex]A+B=153[/tex]

[tex]A=153-B[/tex] --- (1)

[tex]4.25A+5.45B =758.25[/tex] --- (2)

Substituting equation (1) in (2) to get:

[tex]4.25(153-B)+5.45B=758.25[/tex]

[tex]650.25-4.25B+5.45B=758.25[/tex]

[tex]1.2B=758.25-650.25[/tex]

[tex]1.2B=108[/tex]

B = 90 pounds

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