The amount of water present in the given number of moles is 3.603 g.
The given parameters;
- Molar mass of water (H₂O), m = 18.015 g/mol
- Number of moles of the water, n = 0.2 mol
The amount of water present in the given number of moles is calculated as follows;
mass = molar mass x number of moles
mass = 18.015 g/mol x 0.2 mol
mass = 3.603 g
Thus, the amount of water present in the given number of moles is 3.603 g.
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