Need steps for both questions

11.
6x-3y=18
-3y=-6x+18
y = (-6x +18)/-3
y = 2x - 6
12.
-3x-7y=14
-7y=3x+14
y=(-3/7)x - 2
Answer:
[tex]\large\boxed{Q10.\ y=2x-6}\\\boxed{Q12.\ y=-\dfrac{3}{7}x-2}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
Q 10.
[tex]6x-3y=18[/tex] subtract 6x from both sides
[tex]6x-6x-3y=-6x+18[/tex]
[tex]-3y=-6x+18[/tex] divide both sides by (-3)
[tex]\dfrac{-3y}{-3}=\dfrac{-6}{-3}x+\dfrac{18}{-3}\\\\y=2x-6[/tex]
Q 12.
[tex]-3x-7y=14[/tex] add 3x to both sides
[tex]-3x+3x-7y=3x+14[/tex]
[tex]-7y=3x+14[/tex] divide both sides by (-7)
[tex]\dfrac{-7y}{-7}=\dfrac{3}{-7}x+\dfrac{14}{-7}\\\\y=-\dfrac{3}{7}x-2[/tex]