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how many moles of gas will occupy a volume of 0.53 L at a temperature of 329 K and pressure of 3.0 atm? n= ..... mol

Respuesta :

you have to rewrite the ideal gas law in terms of n. (n=PV/RT)
you are given V=0.53L, T=329K, and P=3.0atm, R is a constant so you already know that R=0.08206atmL/molK.
n=(3.0atmx0.53L)/(0.08206atmL/molKx329K)
n=0.0589mol gas

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