Respuesta :
Answer;
= 1.23 moles
Explanation;
V1/n1 = V2/n2
V1 = 55 L, n1 =2.46 moles
1/2 of the gas was used and thus; 1/2 or 27.5 L remained.
Therefore;
55 L/2.46 moles = 27.5 L/ n2
n2 = (2.46 × 27.5)/55
= 1.23 moles
The number of moles if 1/2 of the gas is used is mathematically given as
n2= 1.23 moles
What would the number of moles if 1/2 of the gas is used?
Question Parameter(s):
a propane tank containing 55l
has 2.46 moles of the gas C3 is propane
Generally, the equation for the volume is mathematically given as
V1/n1 = V2/n2
Therefore
55 L/2.46 = 27.5 L/ n2
n2 = (2.46 * 27.5)/55
n2= 1.23 moles
In conclusion, the number of moles
n2= 1.23 moles
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