Respuesta :

Answer;

= 1.23 moles

Explanation;

V1/n1 = V2/n2

V1 = 55 L, n1 =2.46 moles

1/2 of the gas was used and thus; 1/2 or 27.5 L remained.

Therefore;

55 L/2.46 moles = 27.5 L/ n2

n2 = (2.46 × 27.5)/55

    = 1.23 moles

The number of moles if 1/2 of the gas is used is mathematically given as

n2= 1.23 moles

What would the number of moles if 1/2 of the gas is used?

Question Parameter(s):

a propane tank containing 55l

has 2.46 moles of the gas C3 is propane

Generally, the equation for the volume  is mathematically given as

V1/n1 = V2/n2

Therefore

55 L/2.46  = 27.5 L/ n2

n2 = (2.46 * 27.5)/55

n2= 1.23 moles

In conclusion, the number of moles

n2= 1.23 moles

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