can you answer this

Answer:
A.) [tex]6a=2(p+3q)[/tex]
Step-by-step explanation:
Given: [tex]p=3(a-q)[/tex]; solve for 6a.
If we want to solve for [tex]6a[/tex], we need to know what the value for [tex]a[/tex] is. To do that, we need to isolate [tex]a[/tex] on one side of the equal sign. Before we even do that, let's distribute this problem out.
[tex]p=3a-3q[/tex]
Now, let's move [tex]3a[/tex] to the left side of the equation.
[tex]-3a+p=-3q[/tex]
Let's move [tex]p[/tex] over so we have the [tex]a[/tex] on one side of the equation.
[tex]-3a=-p-3q[/tex]
To solve for [tex]a[/tex], we need to take off the coefficient that is on [tex]a[/tex] (-3.) To do this, divide everything by -3.
[tex]a=\frac{p}{3}+q[/tex]
Now, we know what the value of [tex]a[/tex] is. To find the value of [tex]6a[/tex], multiply everything by 6.
[tex]6a=\frac{6p}{3}+6q[/tex]
Simplify.
[tex]6a=2p+6q[/tex]
Factor.
[tex]6a=2(p+3q)[/tex]