Answer : The correct option is, (1) [tex]P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s)[/tex]
Explanation :
The two intermediate chemical equations are :
[tex]P_4O_6(s)\rightarrow P_4(s)+3O_2(g)[/tex] ..............(1)
[tex]P_4(s)+5O_2(g)\rightarrow P_4O_{10}(s)[/tex] .............(2)
Now adding equation (1) and equation (2), we get
[tex]P_4O_6(s)+P_4(s)+5O_2(g)\rightarrow P_4(s)+3O_2(g)+P_4O_{10}(s)[/tex]
Now we will cancel the [tex]P_4(s)[/tex] from both the sides of the equation, we get
[tex]P_4O_6(s)+5O_2(g)\rightarrow 3O_2(g)+P_4O_{10}(s)[/tex]
Now we will subtracting [tex]3O_2(g)[/tex] from the [tex]5O_2(g)[/tex], we get
[tex]P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s)[/tex]
This is the final chemical equation.
