Answer:
h(x) = x - 5
set of all integers except 3
-∞ ≤ x ≤ ∞ and x ≠ 3
Step-by-step explanation:
Given the two equations in the question
Equation 1
f(x) = x² − 8x + 15
Equation 2
g(x) = x − 3
To find equation 3 that is h(x) we need to divide f(x) by g(x)
f(x) / g(x)
x² − 8x + 15 / x − 3
By using quadratic factorisation
(x-3)(x-5) / (x-3)
Cancel (x-3) from both numerator and denominator
h(x) = x-5
The domain of h(x)
set of all integers except 3
-∞ ≤ x ≤ ∞ and x≠3
