Zn +2 HCl ---------> ZnCl2 + H2
17.0 g H2 * 1 mol H2 / (2 * 1.008 g H2) * (1 mol Zn / 1 mol H2) =
8.432 mol Zn required
8.432 mol Zn * (65.39 g Zn / mol Zn) = 551.4 g Zn
Answer:
Explanation:
the balanced chemical equation for the displacement reaction between zinc and hydrchloric acid is given as
Zn + 2HCl → ZnCl₂ + H₂
mole ratio; 1 : 2 1 : 1
atomic mass of Zinc = 65.38g
atomic mass of hydrogen =1g
molecular mass of hydrgen(H₂) = 1×2=2g
from the chemical reaction above, it can be deduced that;
2g of hydrgen gas is produced from 65.38g of solid zinc
∴ 14.4g of hydrogen will be needing xg of solid zinc
x=[tex]\frac{14.4 X 65.38}{2}[/tex]
x = 941.472 ÷ 2
x=470.7g
14.4g of hydrogen requires 470.7g of solid zinc
