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Use the graph below to answer the question that follows:

cosine graph with points at 0, negative 1 and pi over 2, 3, and pi, negative 1

What are the amplitude, period, and midline of the function?

Respuesta :

Answer:

For this case the amplitude is given by:

 A = (l-5l + 3) / 2

 A = 8/2

 A = 4

 The middle line is given by:

 y = -1

 The period of the function is given by:

 T = l x2 - x1 l

 T = l 0 - 2pi l

 T = l - 2pi l

 T = 2pi

 Answer:

 Amplitude: 4; period: 2π; midline: y = -1

Step-by-step explanation:

pi

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