Answer: OPTION A
Step-by-step explanation:
Descompose the number 20 into its prime factors:
[tex]20=2*2*5=2^2[/tex]
Because, by definition:
[tex]\sqrt[n]{a^n}=a[/tex]
Then, you must rewrite 2²*5 inside of the square root, as following;
[tex]\frac{3\sqrt{2^2*5}}{\sqrt{5}}[/tex]
Simplify as following:
Keeping on mind that [tex]\sqrt[n]{a^n}=a[/tex], then:
[tex]\frac{3*2\sqrt{5}}{\sqrt{5}}[/tex]
Note:
[tex]\frac{\sqrt{5}}{\sqrt{5}}=1[/tex]
Then:
[tex]\frac{6\sqrt{5}}{\sqrt{5}}=6(1)=6[/tex]
Therefore, as you can see the answer is the option A
