Respuesta :
car normally has 4 wheeles
motorcycles normall have 2 wheels
c=cars
m=motorcycles
4c+2m=98
c+m=30
multiply second equation by -2 and add to the original equaiton
-2c-2m=-60
4c+2m=98 +
2c+0m=38
2c=38
divide 2
c=19
sub
c+m=30
19+m=30
m=11
11 motorcycles
19 cars
motorcycles normall have 2 wheels
c=cars
m=motorcycles
4c+2m=98
c+m=30
multiply second equation by -2 and add to the original equaiton
-2c-2m=-60
4c+2m=98 +
2c+0m=38
2c=38
divide 2
c=19
sub
c+m=30
19+m=30
m=11
11 motorcycles
19 cars
x ➡ cars 4 wheels
y ➡ motorcycles 2 wheels
4x +2y = 98
x + y = 30
use either substitution or elimination to solve, the answer will be 19 cars and 11 motorcycles.
y ➡ motorcycles 2 wheels
4x +2y = 98
x + y = 30
use either substitution or elimination to solve, the answer will be 19 cars and 11 motorcycles.