Respuesta :
iron (III) chloride's chemical fromula is FeCl₃ Since Fe (III) is Fe³⁺ and Cl is Cl⁻. Given that, you know that 3 moles of Cl⁻ combines with 1 mole of FeCl₃.
First you need to find the number of moles of Cl⁻ is contained in 2.35x10^23 atoms of Cl⁻. To do this you need to divide the number of Cl⁻ atoms by Avogadro's number (6.02x10^23atoms/mol) to get 0.3902 moles of Cl⁻. Then you multiply 0.3902 by 1/3 (using the fact that there is 1mol Fe³⁺ per 3mol Cl⁻) to get the number of moles of FeCl₃ which is 0.1301mol FeCl₃. Then to find the mass FeCl₃, you need to multiply the number of moles of FeCl₃ (which is 0.1301mol) by the molar mass of FeCl₃ (which is 162.15g/mol) to get 21.09g FeCl₃.
therefore the amount of FeCl₃ is 21.09g FeCl₃.
I hope this helps. let me know in the comments if anything is unclear.
First you need to find the number of moles of Cl⁻ is contained in 2.35x10^23 atoms of Cl⁻. To do this you need to divide the number of Cl⁻ atoms by Avogadro's number (6.02x10^23atoms/mol) to get 0.3902 moles of Cl⁻. Then you multiply 0.3902 by 1/3 (using the fact that there is 1mol Fe³⁺ per 3mol Cl⁻) to get the number of moles of FeCl₃ which is 0.1301mol FeCl₃. Then to find the mass FeCl₃, you need to multiply the number of moles of FeCl₃ (which is 0.1301mol) by the molar mass of FeCl₃ (which is 162.15g/mol) to get 21.09g FeCl₃.
therefore the amount of FeCl₃ is 21.09g FeCl₃.
I hope this helps. let me know in the comments if anything is unclear.
