Respuesta :

( 3x + 2y = 1 ) * 4
( 4x + 3y = -2 )  *3

12x + 8y = 4 --> equation 1
12x + 9y = -6  --> equation 2
-12x - 9y = 6 ---> equation 3 ( changing signs. )
eliminating the x values and adding the like terms

-y = 10
y = -10

Substituting the value of y in equation 1
3x + 2(-10 ) = 1
3x -20 = 1
3x = 21
x = 7

So, X = 7 and Y = -10

Hope this helps...  :)


[tex] \left \{ {{3x+2y=1} \atop {4x+3y=-2}} \right. [/tex]

Multiply [tex]3x+2y=1 [/tex] by 4 [tex]12 x+8y=4[/tex]

Multiply[tex]4x+3y=-2[/tex] by 3  [tex]12x+9y=-6[/tex]

[tex] \left \{ {{12x+8y=4} \atop {12x+9y=-6}} \right. [/tex]

[tex] \left \{ {{12x+9y=-6} \atop {12x+8y=4}} \right. -[/tex]

[tex]y = -10[/tex]

[tex] \left \{ {{12x+8y=4} \atop {y=-10}} \right. [/tex]

for [tex]12x+8y=4[/tex] plug in [tex]y=-10[/tex]

[tex]12x+8(-10) = 4[/tex]

[tex]12x - 80 = 4[/tex]

Add 80 to both sides:

[tex]12 x = 4 + 80[/tex]

[tex]12 x = 84[/tex]

Divide both sides by 12 :

[tex]x = \frac{84}{12} [/tex]

[tex]x = 7[/tex]

[tex]x = 7 , y = -10[/tex]

hope this helps!