Respuesta :
( 3x + 2y = 1 ) * 4
( 4x + 3y = -2 ) *3
12x + 8y = 4 --> equation 1
12x + 9y = -6 --> equation 2
-12x - 9y = 6 ---> equation 3 ( changing signs. )
eliminating the x values and adding the like terms
-y = 10
y = -10
Substituting the value of y in equation 1
3x + 2(-10 ) = 1
3x -20 = 1
3x = 21
x = 7
So, X = 7 and Y = -10
Hope this helps... :)
( 4x + 3y = -2 ) *3
12x + 8y = 4 --> equation 1
12x + 9y = -6 --> equation 2
-12x - 9y = 6 ---> equation 3 ( changing signs. )
eliminating the x values and adding the like terms
-y = 10
y = -10
Substituting the value of y in equation 1
3x + 2(-10 ) = 1
3x -20 = 1
3x = 21
x = 7
So, X = 7 and Y = -10
Hope this helps... :)
[tex] \left \{ {{3x+2y=1} \atop {4x+3y=-2}} \right. [/tex]
Multiply [tex]3x+2y=1 [/tex] by 4 [tex]12 x+8y=4[/tex]
Multiply[tex]4x+3y=-2[/tex] by 3 [tex]12x+9y=-6[/tex]
[tex] \left \{ {{12x+8y=4} \atop {12x+9y=-6}} \right. [/tex]
[tex] \left \{ {{12x+9y=-6} \atop {12x+8y=4}} \right. -[/tex]
[tex]y = -10[/tex]
[tex] \left \{ {{12x+8y=4} \atop {y=-10}} \right. [/tex]
for [tex]12x+8y=4[/tex] plug in [tex]y=-10[/tex]
[tex]12x+8(-10) = 4[/tex]
[tex]12x - 80 = 4[/tex]
Add 80 to both sides:
[tex]12 x = 4 + 80[/tex]
[tex]12 x = 84[/tex]
Divide both sides by 12 :
[tex]x = \frac{84}{12} [/tex]
[tex]x = 7[/tex]
[tex]x = 7 , y = -10[/tex]
hope this helps!
Multiply [tex]3x+2y=1 [/tex] by 4 [tex]12 x+8y=4[/tex]
Multiply[tex]4x+3y=-2[/tex] by 3 [tex]12x+9y=-6[/tex]
[tex] \left \{ {{12x+8y=4} \atop {12x+9y=-6}} \right. [/tex]
[tex] \left \{ {{12x+9y=-6} \atop {12x+8y=4}} \right. -[/tex]
[tex]y = -10[/tex]
[tex] \left \{ {{12x+8y=4} \atop {y=-10}} \right. [/tex]
for [tex]12x+8y=4[/tex] plug in [tex]y=-10[/tex]
[tex]12x+8(-10) = 4[/tex]
[tex]12x - 80 = 4[/tex]
Add 80 to both sides:
[tex]12 x = 4 + 80[/tex]
[tex]12 x = 84[/tex]
Divide both sides by 12 :
[tex]x = \frac{84}{12} [/tex]
[tex]x = 7[/tex]
[tex]x = 7 , y = -10[/tex]
hope this helps!