Respuesta :
Answer:
B. 2.77 · 10^28
Step-by-step explanation:
The total number of atoms is ...
(6.02·10^23 atoms/mol)·(4.6·10^4 mol) = (6.02·4.6)·10^(23+4) atoms
≈ 27.7·10^27 atoms
≈ 2.77·10^28 atoms . . . . . . put in scientific notation form
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Scientific notation has one non-zero digit to the left of the decimal point and the exponent adjusted accordingly.
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Your calculator can help you figure this out. If necessary, put the display into scientific notation mode. (For numbers this size, it is usually not necessary.)

Answer: B. [tex]2.77\times10^{28\text{ atoms}}[/tex]
Step-by-step explanation:
Given : One mole of a chemical element contains approximately [tex]6.02\times10^{23}\text{ atoms}[/tex]
Then , the number of atoms present in [tex]4.6\times10^{4}\text{ moles}[/tex] is given by :-
[tex]6.02\times10^{23}\times4.6\times10^{4}\\\\=6.02\times4.6\times10^{23}\times10^{4}[/tex]
Using exponents property:
[tex]a^m\times a^n=a^{m+n}[/tex]
[tex]=27.692\times10^{23+4}\\\\\approx2.77\times10^{23+4+1}=2.77\times10^{28\text{ atoms}}[/tex]