One number is half another number. The sum of the two numbers is 141. Find the numbers.


Restate the applied problem.

You must translate the words into a system of equations for solving the problem.

Solve the system of equations for the answers. You must provide detailed step-by-step explanations on how you solved the problem.

Explain in detail how you would check your answers.

Respuesta :

Answer:

x = 47

y = 94

Step-by-step explanation:

Givens

Let the larger number = y            Note: y must be even. Why is that?

Let the smaller number = x

Equations

x = 1/2 y

x + y = 141

Solution

Substitute x from the first equation into the second equation

1/2 y + y = 141

Change 1/2 y to 0.5y

0.5y + y = 141

Combine the left

1.5y = 141

Divide both sides by 1.5

1.5y/1.5 = 141/1.5

Do the division

y = 94                      And y is even.

================

x = 1/2y

x = 1/2*94

x = 47

Check

The smaller number is 1/2 the larger one This is correct.

47 + 94 = 141 and this also checks.

Answer:

x = 47

y = 94

Step-by-step explanation:

We know that one number is half another number and the sum of these two numbers is 141. We are to find the numbers.

Assuming [tex]x[/tex] and [tex]y[/tex] to be the numbers, we can write it as:

[tex]x=\frac{1}{2}y [/tex] --- (1)

[tex]x+y=141[/tex] --- (2)

Substituting the value of [tex]x[/tex] from (1) into (2) to get:

[tex]\frac{1}{2}y+y=141[/tex]

[tex]\frac{3}{2}y+y=141[/tex]

[tex]y=141 \times \frac{2}{3}[/tex]

y = 94

Now substituting this value of [tex]y[/tex] in (1):

[tex]x=\frac{1}{2} \times 94 [/tex]

x = 47

Translating it in other words:

One number is double the other number and the sum of the two number is 141.

Checking answers:

[tex]x=\frac{1}{2}y [/tex]

[tex]47=\frac{1}{2} \times 94[/tex]

[tex]47=47 [/tex]

[tex]x+y=141[/tex]

[tex]47+94=141[/tex]