Given: arc IP + arc VK = 86°
Find: ∠KSP

Check the picture below.
using the intersecting chords theorem, let's see, we know that ∡IOP is 43° and since the angle across the junction is a vertical angle, is its twin.
let's recall that a circle has a total of 360°, so if we subtract those two vertical angles, namely 360 - 43 - 43 = 274°.
so the remaining two angles, which are also vertical angles, and therefore twins as well, each one will take 274 ÷ 2 = 137°.
Answer:
The measure of angle KSP is [tex]137\°[/tex]
Step-by-step explanation:
step 1
Find the measure of angle ISP
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
[tex]m<ISP=\frac{1}{2}(arc\ VK+arc\ IP)[/tex]
we have
[tex](arc\ VK+arc\ IP)=86\°[/tex]
substitute
[tex]m<ISP=\frac{1}{2}(86\°)=43\°[/tex]
step 2
Find the measure of angle KSP
we know that
[tex]m<ISP+m<KSP=180\°[/tex] ----> by supplementary angles
we have
[tex]m<ISP=43\°[/tex]
substitute
[tex]43\°+m<KSP=180\°[/tex]
[tex]m<KSP=180\°-43\°=137\°[/tex]