Answer:
Part 1) [tex]f(x)=-(2/3)x-2[/tex]
Part 2) [tex]f(-2)=-2/3[/tex]
Step-by-step explanation:
step 1
Find the equation of the line
Let
[tex]A(-3,0), B(0,-2)[/tex]
The equation of the line into slope intercept form is equal to
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-coordinate of the y-intercept
In this problem
The point B is the y-intercept
so
b=-2
Find the slope m
[tex]m=(-2-0)/(0+3)=-2/3[/tex]
substitute
[tex]y=-(2/3)x-2[/tex]
In function notation
[tex]f(x)=-(2/3)x-2[/tex]
step 2
Find f(-2)
substitute the value of x=-2 in the function
[tex]f(-2)=-(2/3)(-2)-2=(4/3)-2=-2/3[/tex]