Answer with explanation:
Number on the Spinner are ={1,2,3,4}=4 in number
A= Spinning an even number
B= 3 on the spinner
Probability of an event
[tex]=\frac{\text{Total favorable outcome}}{\text{Total possible outcome}}[/tex]
Probability of getting an even number
= Either 2, or 4 from the set of 4 numbers.
[tex]=\frac{2}{4}\\\\=\frac{1}{2}[/tex]
Probability of getting 3 on the spinner
[tex]=\frac{1}{4}[/tex]
→A ∩ B=Getting an even number ∩ 3 on the Spinner
={2,4} ∩ {3}
= 0
P (A ∩ B )=0
→→P (A ∩ B)= Probability of spinning an even number and then a 3 on the spinner
As two events are mutually exclusive,that is A and B are disjoint.
So, P ( A∩B)=0
It should be,
→P(A ∪ B) =P(A) + P (B)- P (A ∩ B)
[tex]=\frac{2}{4}+\frac{1}{4}\\\\=\frac{3}{4}[/tex]
Latricia is Incorrect.
Option B
Latricia’s solution is inaccurate. Her solution describes the probability of spinning an even number or a 3 in the same spin.
