Answer:
[tex]\large\boxed{\left[\begin{array}{ccc}-5&-6\\1&-4\end{array}\right] }[/tex]
Step-by-step explanation:
[tex]\left[\begin{array}{ccc}-3&4\\2&-5\end{array}\right] \times\left[\begin{array}{ccc}3&-2\\1&0\end{array}\right] \\\\=\left[\begin{array}{ccc}(-3)(3)+(4)(1)&(-3)(-2)+(4)(0)\\(2)(3)+(-5)(1)&(2)(-2)+(-5)(0)\end{array}\right]\\\\=\left[\begin{array}{ccc}-9+4&-6+0\\6-5&-4+0\end{array}\right] \\\\=\left[\begin{array}{ccc}-5&-6\\1&-4\end{array}\right][/tex]
