Answer:
3g
Explanation:
The acceleration of gravity on the surface of a planet is given by
[tex]g=\frac{GM}{R^2}[/tex]
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
Calling M the mass of the Earth, R its radius, and g its acceleration due to gravity, we have
[tex]M' = \frac{1}{3}M[/tex] is the mass of planet Z-34
[tex]R'=\frac{1}{3}R[/tex] is the radius of Z-34
We can ignore the different spin rate since the gravitational acceleration does not depend on that
So, the value of g on planet Z-34 will be
[tex]g'=\frac{GM'}{R^2}=\frac{G(\frac{1}{3}M)}{(\frac{1}{3}R)^2}=\frac{1/3}{1/9}\frac{GM}{R^2}=3 g[/tex]
so, the correct answer is 3g
