Answer:
Since you have not included a picture of the graph, I cannot tell you which specific graph it is, but I can describe it. The graph will have a y-intercept at -0.5 and a slope of -2/16.
Step-by-step explanation:
To get this information you must put it in slope intercept form. y=mx+b.
What I did first was transfer the -16y over.
-2x-16y=8
-2x=16y+8
Next, I transferred the 8 over, which gives us
-2x-8=16y
Finally, I divided by 16, to isolate the y, which gives you
-2x/16 -8/16=y, which simplifies to -2x/16 - .05=y.
Using this you can determine the y- intercept, -0.5, anf the slope -2/16.
ANSWER
See attachment.
EXPLANATION
The given linear equation is
-2x - 16y = -8
Let us rewrite this in the slope intercept form,
[tex] - 16y = 2x - 8[/tex]
Divide through by -16.
[tex]y = - \frac{1}{8} x + \frac{1}{2} [/tex]
The slope of this graph is
[tex]m = - \frac{1}{8} [/tex]
and the y-intercept is ½.
The x-intercept is found by plugging in y=0.
-2x-16(0)=-8
-2x=-8
x=4
The x-intercept is (4,0)
We can use the slope,the x-intercept and the y-intercept to identify the graph to be the one shown in the attachment.
