Respuesta :
Answer:
x < 3 and x > 2
Step-by-step explanation:
We are to solve for 4x - 4 < 8 and 9x + 5 > 23
So 4x - 4 < 8,
4x < 8 + 4
4x < 12
x < 12/4
x < 3
And for
9x + 5 > 23
9x > 23 - 5
9x > 18
x > 18/9
x > 2
The solution for 4x - 4 < 8 is x < 3
The solution for 9x + 5 > 23 is x > 2
The given inequality is:
4x - 4 < 8
Add 4 to both sides
4x - 4 + 4 < 8 + 4
4x < 12
Divide both sides by 4
[tex]\frac{4x}{4} < \frac{12}{4} \\x < 3[/tex]
The second inequality is:
9x + 5 > 23
Subtract 5 from both sides of the inequality
9x + 5 - 5 > 23 - 5
9x > 18
Divide both sides by 9
[tex]\frac{9x}{9} > \frac{18}{9}\\x > 2[/tex]
The solution for 4x - 4 < 8 is x < 3
The solution for 9x + 5 > 23 is x > 2
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