If the height of the triangle is 3 units more than the base, select the function that represents the area of the triangle.

[tex]A.\\A(b) = \frac{1}{2} b^{2} + 3\\\\B.\\A(b) = 2bx^{2} + 3\\\\C.\\A(b) = \frac{1}{2} (b^{2} + 3b)\\\\D.\\A(b) = bx^{2} + 3b[/tex]

If the height of the triangle is 3 units more than the base select the function that represents the area of the triangle texAAb frac12 b2 3BAb 2bx2 3CAb frac12 class=

Respuesta :

For this case we have that by definition, the area of a triangle is given by:

[tex]A = \frac {1} {2} * b * h[/tex]

Where:

h: It's the height of the triangle

b: It is the base of the triangle.

They tell us that the height of the triangle is 3 units more than the base. That means that if the base is "b" then the height is "b + 3". So, the area is:

[tex]A(b) = \frac {1} {2} * b * (b + 3)\\A(b) = \frac {1} {2} * b ^ 2 + 3b\\A(b) = \frac {b ^ 2 + 3b} {2}[/tex]

ANswer:

Option C