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What is the specific heat of an object that weighs 15 grams and changes temperature from 30°C to 37°C when 50 J of heat is added?

1. 0.48 J/g •°C
2. 0.11 J/g •°C
3. 23.33 J/g •°C
4. 0.09 J/g •°C

Respuesta :

superman1987

Answer:

0.4762 J/g°C.

Explanation:

  • It is known that:

The amount of heat released to water = Q = m.c.ΔT.

where, m is the mass of water (m = 15.0 g).

c is the specific heat capacity of water = ??? J/g°C.

ΔT is the temperature difference = (final T - initial T = 37.0°C - 30.0°C = 7.0°C).

∴ The specific heat capacity of water = c = Q/m.ΔT = (50.0 J)/(15.0 g)(7.0°C) = 0.4762 J/g°C.

adefioyelaoye

The specific heat of the object is 0.4762 J/g°C.

What is Specific heat capacity?

This is defined as the amount of heat energy required to raise the temperature of a substance per unit of mass.

Q = m.c.ΔT where,

m is the mass of water = 15.0 g.

c is the specific heat capacity of water = ??? J/g°C.

ΔT is the temperature difference = 37.0°C - 30.0°C = 7.0°C.

Specific heat capacity of water (c) = Q/m.ΔT

= (50.0 J)/(15.0 g)(7.0°C)

= 0.4762 J/g°C.

Read more about Specific heat capacity here https://brainly.com/question/1401668

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