In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 56.8 minutes. What is the frequency of this oscillations?

Respuesta :

Answer: [tex]2.9(10)^{-4} Hz[/tex]

The frequency is defined as the inverse of the period [tex]T[/tex] (time):

[tex]f=\frac{1}{T}[/tex]   (1)

And according to the International Units System its unit is Hertz ([tex]Hz=1/s[/tex]).

This means we have to convert this quantity given in minutes to seconds before solving the equation:

[tex]T=56.8 min.\frac{60s}{1min}=3408s[/tex]   (2)

Substituting (2)in (1):

[tex]f=\frac{1}{3408s}[/tex]

Finally:

[tex]f=0.00029Hz=2.9(10)^{-4} Hz[/tex]