What are the coordinate points to this equation

Answer:
[tex]\large\boxed{x^2+(y-3)^2=2.25}[/tex]
Step-by-step explanation:
The standard form of an equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have the center (0, 3) and the point (-1.5, 3) on the circumference.
The radius is a distance between given points: r = 1.5.
Substitute:
[tex](x-0)^2+(y-3)^2=(1.5)^2[/tex]