Answer:
(8,0)
Step-by-step explanation:
The equation that models the path traced by the ball is
[tex]h(x)=-8x^2+64x[/tex]
To find the point at which the ball hit the ground, we must equate the function to zero.
[tex]-8x^2+64x=0[/tex]
Factor;
[tex]-8x(x-8)=0[/tex]
[tex]-8x=0,(x-8)=0[/tex]
This implies that;
x=0,x=8,
At x=0, the ball was not yet kicked.
So we take x=8, to be the time the ball hit the ground.
We substitute x=8 into the function to get;
[tex]h(8)=-8(8)^2+64(8)=0[/tex]
Hence the point at which the ball hit the ground is (8,0)
