Answer:
[tex]-6.25\cdot 10^7 J[/tex]
Explanation:
The gravitational potential at a point on the Earth surface is given by:
[tex]U=-\frac{GM}{R^2}[/tex]
where
G=6.67×10^-11Nm^2kg^-2 is the gravitational constant
M=5.98×10^24kg is the Earth's mass
R=6.38×10^6 m is the Earth's radius
Substituting the numbers into the equation, we find
[tex]U=-\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.38\cdot 10^6)}=-6.25\cdot 10^7 J[/tex]
