Answer:
The general form is;
[tex]x^2+y^2+6x-8y+21=0[/tex]
Step-by-step explanation:
The given circle has center (h,k)= (-3,4) and radius r=2 units.
The equation of the circle is found using the formula;
[tex](x-h)^2+(y-k)^2=r^2[/tex]
We plug in the values to get;
[tex](x+3)^2+(y-4)^2=2^2[/tex]
[tex](x+3)^2+(y-4)^2=4[/tex]
Expand;
[tex]x^2+6x+9+y^2-8y+16=4[/tex]
[tex]x^2+y^2+6x-8y+16+9-4=0[/tex]
The general form is;
[tex]x^2+y^2+6x-8y+21=0[/tex]
