Answer:
Water is relatively weak field.
Explanation:
Here's a good example... :
[Mn(H2O)6]2+:
Total electron count = -7 (Mn) - 12 (water ligands) + 2 (charge) = -17, 17 e-
Oxidation state, +2 = Mn + (0), Mn = +2, Mn(II)
d electrons, +2 (oxidation state) - 7 (valence electrons) = -5, d5
Because Mn is a first row transition metal, relatively low oxidation state, with a weak field ligand, the complex will be high spin with 5 unpaired electrons.
So if you have a weak ligand, the complex is high spin.
