let's recall that the diameter is always twice as long as the radius, namely if the diameter is 8, its radius is 4 then.
[tex]\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=4 \end{cases}\implies A=\pi 4^2\implies A=16\pi \implies A\approx 50.27[/tex]
Answer:
The area of given triangle is 50.14 in²
Step-by-step explanation:
Formula:-
Area of circle = πr²
Where r is the radius of circle
To find the area of triangle
Here diameter of circle = 8 in
Radius r = diameter/2 = 8/2 = 4 in
Area = πr² = 3.14 * 4²
= 3.14 * 16 = 50.14 in²
Therefore the area of given triangle is 50.14 in²
