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A right rectangular prism has a length of 10 in., a width of 12 in., and a height of 16 in. The dimensions of the prism are halved. What is the surface area of the reduced prism? Enter your answer in the box. in²

Respuesta :

kudzordzifrancis

Answer:

[tex]S.A=236in^2[/tex]

Step-by-step explanation:

The given prism has dimension;

[tex]L=10in.,W=12in.,H=16in.,[/tex]

If the dimensions of the prism are halved then;

[tex]l=5in.,w=6in.,h=8in.,[/tex]

The surface area of the reduced prism will be;

[tex]S.A=2(lw+lh+wh)[/tex]

[tex]S.A=2(5(6)+5(8)+6(8))[/tex]

[tex]S.A=2(30+40+48)[/tex]

[tex]S.A=2(118)[/tex]

[tex]S.A=236in^2[/tex]

ShyzaSling

Answer:

236in²

Step-by-step explanation:

Given in the question,

length of rectangular prism  = 10 in

width of rectangular prism  = 12 in

height of the prism = 16 in

Since the dimensions are reduced to half so the new dimensions are

length of rectangular prism  = 5 in

width of rectangular prism  = 6 in

height of the prism = 8 in

Formula to calculate the surface area

2(lw + lh + wh)

2 ((5x6) + (8x5) + 2(6x8))

236 in²

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