Answer:
x= 0 and x=-3/4
Step-by-step explanation:
[tex]4x^2 + 3x =0[/tex]
We need to solve this equation using quadratic formula.
The quadratic formula is:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
for the type of equation
[tex]ax^2 +bx+c=0[/tex]
So, for our given equation:
a= 4
b= 3
c=0
putting values in the formula
[tex]x=\frac{-3\pm\sqrt{9-0}}{8}\\x=\frac{-3\pm3}{8}\\x=\frac{-3+3}{8}\,and\, x=\frac{-3-3}{8}\\x=\frac{0}{8}\,and\, x=\frac{-6}{8}\\x=0\,and\, x=\frac{-3}{4}[/tex][/tex]
so, x= 0 and x=-3/4.
