Respuesta :

gmany

Answer:

[tex]\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }[/tex]

Step-by-step explanation:

[tex]A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right][/tex]