Respuesta :

gmany

Step-by-step explanation:

[tex]20p^2-64p+12=4(5p^2-16p+3)=4\bigg(5p^2-15p-p+3\bigg)\\\\=4\bigg(5p(p-3)-1(p-3)\bigg)=4(p-3)(5p-1)[/tex]