Answer:
[tex]y= \frac{+6\sqrt{2}+3}{4}[/tex]
[tex]y= \frac{-6\sqrt{2}+3}{4}[/tex]
Step-by-step explanation:
(4y – 3)^2 = 72
To find the solution for the given equation we need to solve for y
To remove square we take square root on both sides
[tex]4y-3 = \sqrt{72}[/tex]
When we take square root we put +-
square root (72) = square root (36 *2) = 6sqrt(2)
[tex]4y-3 = +-6\sqrt{2}[/tex]
Now we add 3 on both sides
[tex]4y =+-6\sqrt{2}+3[/tex]
Divide both sides by 4
[tex]y= \frac{+-6\sqrt{2}+3}{4}[/tex]
[tex]y= \frac{+6\sqrt{2}+3}{4}[/tex]
[tex]y= \frac{-6\sqrt{2}+3}{4}[/tex]
