Answer:
[tex](x +3)^2 + (y-4)^2 = 4[/tex]
Step-by-step explanation:
The general equation of a circle is
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
In this equation, 'r' represents the radius of the circle and (h,k) represents the central point of the circle.
Radius of the circle is half of the diameter = d/2
From figure, ther diameter of the circle is calculated using (y2-y1) or (x2-x1)
In this figure,
y2 = 6
y1 = 2
d = (y2 - y1) = 6-2 =4
This can also be verified using the values of x
x2 = -1
x1 = -5
d = (x2 - x1) = (-1 - -5) = (-1 + 5) = 4
Also,
r = d/2 = 4/2
r = 2
h represents the horizental distance and k represents the vertical distance of the center of the circle from the origan (0,0).
Therefore,
h = 0 - 3 = -3 as the center of circle is 3 units left to the origan
k = 0 + 4 = 4 as the center of circle is 4 units above to the origan
Therefore the equation of circle becomes
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
[tex](x-(-3))^2 + (y-(4))^2 = 2^2[/tex]
[tex](x +3)^2 + (y-4)^2 = 4[/tex]
