Thank you for any help!

The answer is D
0 is not less than or equal to -4, and in the second equation, 0 is greater than -1
Answer:
D. No. (0, 0) satisfies [tex]y>2x-1[/tex] but does not satisfy [tex]y\leq x^2-4[/tex].
Step-by-step explanation:
We are given the following system of equations and we are to determine if (0, 0) is its solution or not:
[tex]y\leq x^2-4[/tex]
[tex]y>2x-1[/tex]
Substituting the given point [tex](0, 0)[/tex] in both the equations to check if it satisfies them.
[tex]y\leq x^2-4[/tex] [tex]\implies[/tex] [tex]0\leq (0)^2-4 \implies 0\leq -4[/tex] - False
[tex]y>2x-1 \implies 0 > 2(0)-1 \implies 0>-10[/tex] - True
Therefore, the correct answer option is D. No. (0, 0) satisfies [tex]y>2x-1[/tex] but does not satisfy [tex]y\leq x^2-4[/tex].