Answer:
-4.10
Step-by-step explanation:
We have so solve [tex](7\tfrac{4}{9}-8)(3.6)-(1.6)(\frac{1}{8}-\frac{3}{4})+1\tfrac{2}{5}\div (-0.35)[/tex]
To solve this expression we will use BODMAS.
B ⇒ Bracket
O ⇒ open
D ⇒ Divide
M ⇒ Multiplication
A ⇒ Addition
S ⇒ Subtraction
First we will solve inside the brackets.
(1) [tex](7\tfrac{4}{9}-8)=\frac{69}{9}-8=(\frac{67-72}{9})=(\frac{-5}{9})[/tex]
(2) [tex](\frac{1}{8}-\frac{3}{4})=\frac{1-6}{8}=(\frac{-5}{8})[/tex]
Now expression becomes
[tex](\frac{-5}{9})(3.6)-(1.6)(\frac{-5}{8})+\frac{7}{5}\div (-0.35)[/tex]
= [tex](-5)(0.04)-(0.02)(-5)+\frac{7}{5}\times \frac{1}{(-0.35)}[/tex]
= [tex](-0.20)-(-0.10)+\frac{1}{5(-0.05)}[/tex]
= [tex]-.20+.10-\frac{1}{.25}=-.20+.10-4[/tex]
= -4.20 + 0.10 = -4.10
