Simon took a bike trip over the course of a single day. Sim rode for the following times:
9:00 A.M. to 11:30 A.M. 35 miles

11:30 A.M. to 11:45 A.M. 0 miles (rest)

11:45 A.M. to 2:15 P.M. 25 miles

-Which set of data accurately shows Simon's speeds?

A. Fastest leg: morning: 16 miles per hour Slowest leg: afternoon: 10 miles per hour Average speed, all day: 12 miles per hour

B. Fastest leg: morning: 14 miles per hour Slowest leg: afternoon: 10 miles per hour Average speed, all day: 11.4 miles per hour

C. Fastest leg: afternoon: 25 miles per hour Slowest leg: morning: 17.5 miles per hour Average speed, all day: 20 miles per hour

D. Fastest leg: afternoon: 17.5 miles per hour Slowest leg: morning: 14 miles per hour Average speed, all day: 11.4 miles per hour

because if we divide the 35 miles on the time to get speed so 35/2.5 = 14 miles and the second one divide the 25 miles on the time to get speed so 25/2.5=10 miles and the average by adding 25 to 35 and 2.5 to 2.5 so 60/5=12 miles ( all day )

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eudora eudora · Answer 2 · 2019-08-30T14:40:46+02:00

Answer:

Option B.

Step-by-step explanation:

Travelling time in the morning 9:00 A.M to 11:30 A.M. = 2.5 hours

Distance traveled by Simon in the morning = 35 miles

Average speed of Simon in the morning = [tex]\frac{35}{2.5}[/tex] = 14 mph

Travelling time in the afternoon 11:45 A.M to 2:15 P.M. = 2.5 hours

Distance traveled by Simon in the afternoon = 25 miles

Average speed of Simon in the afternoon = [tex]\frac{25}{2.5}[/tex] = 10 mph

Total time in travelling (2.5 + 2.5 hours and 15 min. rest) = 5.25 hours

total distance covered = 35 + 25 = 60 miles

Average speed for all day = [tex]\frac{60}{5.25}[/tex]

= 11.4 miles per hour

Therefore, Option B is the correct answer.