Respuesta :
Answer:
3x^2+24x=-48 -> one solution, x=-4
4x^2-16x=0 -> has two solutions, x=0 and x=4
5x^2+2=4x -> has no solutions,
3(x+5)^2=-2 -> has no solutions.
Step-by-step explanation:
Answer:
A). 3x² + 24x = -48 ---- one solution x = -4
B). 4x² - 16x = 0 --- two real solutions x = 0, 4
C). 5x² + 2 = 4x ---- has no real solution
D). 3(x + 5)² = -2 ---- has no real solution
Step-by-step explanation:
We will solve each equation to get the solutions.
A).3x² + 24x = -48
we divide this equation by 3
x² + 8x = -16
x² + 8x + 16 = 0
(x + 4)² = 0
x = -4
There is only one solution, x = -4
B). 4x² - 16x = 0
4x(x - 4) = 0
x = 0 and x = 4 are the solutions.
C). 5x² + 2 = 4x
5x² - 4x + 2= 0
We will find the value of discriminant (b²- 4ac)
= (-4)²- 4(5)(2)
= 16 - 40
= -24 < 0
So this equation has no real solution.
D). 3(x + 5)² = -2
(x + 5)² = [tex]-\frac{2}{3}[/tex]
(x + 5) = [tex]\sqrt{-\frac{2}{3} }[/tex]
x = -5 + [tex]\sqrt{-\frac{2}{3} }[/tex]
So this equation has no real solutions.
