Antoine stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), xx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16h(x)=−2x 2 +4x+16 What is the height of the ball at the time it is thrown?

Respuesta :

znk

Answer:

[tex]\boxed{\text{16 ft}}[/tex]

Step-by-step explanation:

h(x) = -2x² + 4x + 16

At the time the ball is thrown,

x = 0

h(0) = -2 × 0² + 4 × 0 + 16 = [tex]\boxed{ \textbf{16 ft}}[/tex]

Answer:

16 meters

Step-by-step explanation:

khan said so

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