Given the following heats of combustion: C2H2(g) = -1300 kJ/mole, H2(g) = -286 kJ/mole, C2H6(g) = -1560 kJ/mole, Calculate the enthalpy change for the following reaction
C2H2(g) + 2H2(g) → C2H6(g)

a. -312 kJ

b. -26 kJ

c. +312 kJ

d. -26 kJ