Answer:
[tex]\boxed{\text{\$10; \$20}}[/tex]
Step-by-step explanation:
Let t = the price of a T-shirt
and j = the price of a pair of jeans
You have a system of two equations:
[tex]\begin{cases}(1)& 2t + j = 40\\(2) & 2(0.5t) + 5(0.5j) = 60\end{cases}\\[/tex]
[tex]\begin{array}{lrcll}(3) & t+ 2.5j & = & 60 &\text{Removed parentheses in (2)}\\(4)& 2t + 5j & = & 120 &\text{Multiplied (3) by 2}\\& 4j & = & 80 &\text{Subtracted (4) from (1)}\\(5)& j & = & 20 &\text{Divided each side by 4} \\& 2t + 20& = & 40 & \text{Substituted (5) into (1)} \\&2t & = & 20 & \text{Subtracted 20 from each side}\\& t & = & 20 & \text{Divided each side by 2}\\\end{array}[/tex]
[tex]\text{The price of a T-shirt is \boxed{\textbf{\$10}}}\\\\\text{and the price of a pair of jeans is \boxed{\textbf{\$20}}}\\[/tex]
Check:
[tex]\begin{array}{rclcrcl}2\times10\ + 20 & = & 40 & \qquad &2(0.5\times10) + 5(0.5\times20)&=&60\\20 + 20 & = & 40 & \qquad &2\times5 + 5\times 10& = &60\\40& = & 40 &\qquad &10 + 50 & = & 60\\& & &\qquad &60 & = & 60\\\end{array}[/tex]
OK.