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What volume in mL of a 0.763 M solution of BaI2 would be required if you wanted 0.0131 moles of solute? _____ mL (Picture Attached)

What volume in mL of a 0763 M solution of BaI2 would be required if you wanted 00131 moles of solute mL Picture Attached class=

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superman1987

Answer:

The right answer is V = 17.2 mL

Explanation:

  • Knowing that the the relation between No. of moles and concentration:

No. of moles = C * V

where,

C is the concentration in morality and

V is the volume in liter

so you can calculate the volume using:

V = (No. of moles / C) = (0.0131 mol / 0.763 mol/L)

V = 0.0172 L

  • Then yo need to convert the volume from Liter to milliliter

 V = 0.0172 L * (1000 mL / 1 L)

  V = 17.2 mL

So, the right answer is V = 17.2 mL

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