Respuesta :

superman1987

Answer:

344.02 g.

Explanation:

  • Knowing that the no. of moles can be calculated using the relation:

no. of moles (n) = mass/molar mass

no. of moles Al(OH)₃ = 4.41 mol & molar mass of Al(OH)₃ = 78.01 g/mol.

∴ mass = no. of moles * molar mass = (4.41 mol)*(78.01 g/mol) = 344.02 g.

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